Maths
What is the vertex of a parabola, and how do you find it?
Quick answer
The vertex is the turning point of a parabola: its lowest or highest point. For y = ax² + bx + c it is at x = −b/2a; put that x back into the equation to get y.
In one sentence
The vertex of a parabola is its turning point: the lowest point of a ∪-shaped curve, or the highest point of a ∩-shaped one.
Explained
The graph of every quadratic, y = ax² + bx + c, is a parabola: a smooth, symmetrical curve shaped like a U. The vertex is the point where the curve stops going down and starts going up (or the other way round). In the UK it is often called the turning point.
ball
bridge
mountain
Which way the parabola opens depends on the sign of a, the number in front of x²:
- a > 0: the parabola opens upwards (∪) and the vertex is its minimum, the lowest point.
- a < 0: the parabola opens downwards (∩) and the vertex is its maximum, the highest point.
The vertical line through the vertex is the axis of symmetry. Fold the graph along it and the two halves match exactly.
The vertex formula. For y = ax² + bx + c, the vertex is at
x = −b ÷ 2a, and the y-coordinate is what you get when you put that x back into the equation.
Where does −b ÷ 2a come from? Look at the points where y = c. Then ax² + bx = 0, so x(ax + b) = 0, which gives x = 0 or x = −b ÷ a. These two points are at the same height, so by symmetry the vertex sits exactly halfway between them: x = −b ÷ 2a. If you prefer a formula for y too, it is y = c − b² ÷ 4a.
You can find the vertex from any of the three usual forms of a quadratic:
- Standard form y = ax² + bx + c: use x = −b ÷ 2a, then work out y.
- Vertex form y = a(x − h)² + k: the vertex is simply (h, k). Watch the sign: y = (x + 4)² − 7 is y = (x − (−4))² − 7, so the vertex is (−4, −7). You turn standard form into vertex form by completing the square.
- Factored (intercept) form y = a(x − p)(x − q): the parabola crosses the x-axis at p and q, so the vertex is halfway between them, at x = (p + q) ÷ 2.
Why does it matter? Whenever something follows a parabola, the vertex answers "what is the most (or least), and when?" A ball thrown upwards with height h = 20t − 5t² metres reaches its vertex at t = −20 ÷ (2 × −5) = 2 seconds, when h = 40 − 20 = 20 m. So it rises to 20 m after 2 seconds, then falls. The vertex is also the middle of the two solutions of a quadratic equation, which is exactly why the quadratic formula starts with −b ÷ 2a.
Examples
| Equation | Form | Working | Vertex | Max or min |
|---|---|---|---|---|
| y = x² − 6x + 5 | standard | x = 6 ÷ 2 = 3; y = 9 − 18 + 5 = −4 | (3, −4) | minimum |
| y = 2x² + 8x + 3 | standard | x = −8 ÷ 4 = −2; y = 8 − 16 + 3 = −5 | (−2, −5) | minimum |
| y = −x² + 4x + 1 | standard | x = −4 ÷ (−2) = 2; y = −4 + 8 + 1 = 5 | (2, 5) | maximum |
| y = 3(x − 1)² + 4 | vertex | read off h = 1, k = 4 | (1, 4) | minimum |
| y = −(x + 2)² + 6 | vertex | read off h = −2, k = 6 | (−2, 6) | maximum |
| y = (x − 1)(x − 5) | factored | x = (1 + 5) ÷ 2 = 3; y = 2 × (−2) = −4 | (3, −4) | minimum |
The first and last rows are the same parabola: (x − 1)(x − 5) multiplies out to x² − 6x + 5, and both methods give (3, −4).
Worked example: find the vertex of y = 2x² − 4x + 5. Here a = 2 and b = −4, so x = −(−4) ÷ (2 × 2) = 4 ÷ 4 = 1. Then y = 2(1)² − 4(1) + 5 = 2 − 4 + 5 = 3. The vertex is (1, 3), and because a = 2 is positive it is the minimum. Check with the y-formula: 5 − 16 ÷ 8 = 5 − 2 = 3. ✓
Common mistakes
- Dropping the minus sign in −b ÷ 2a. For y = x² + 6x + 1, b = 6, so x = −6 ÷ 2 = −3, not 3.
- Getting the sign in vertex form wrong. y = (x − 2)² + 5 has its vertex at (2, 5); y = (x + 2)² + 5 has it at (−2, 5). Ask: which x makes the bracket zero?
- Dividing by 2 and forgetting the a. −b ÷ 2a means −b ÷ (2 × a). For y = 3x² − 12x, x = 12 ÷ 6 = 2, not 12 ÷ 2 = 6.
- Squaring a negative x wrongly. If x = −2, then x² = 4, so 2x² = 8. Put the value in brackets: 2(−2)².
- Assuming the vertex is always the lowest point. If a is negative, the vertex is the highest point.
Step by step
Step by step
- Read a, b and cWrite the quadratic as y = ax² + bx + c and note the signs.
- Find the x-coordinateWork out x = −b ÷ 2a. (In vertex form, read h off instead; in factored form, take the midpoint of the roots.)
- Find the y-coordinateSubstitute that x into the original equation and calculate y.
- Decide max or minIf a > 0 the vertex is a minimum; if a < 0 it is a maximum.
- Check with symmetryPick two x-values the same distance either side of the vertex. They should give the same y.
The axis of symmetry is then the line x = (your x-coordinate). When you sketch the graph, plot the vertex first and work outwards in both directions.
Practice questions
Find the vertex
Try each one, then check your answer.
- Find the vertex of y = (x − 4)² + 1.
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(4, 1) - Find the vertex of y = (x + 3)² − 5.
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The bracket is zero at x = −3: (−3, −5) - Find the vertex of y = −2(x − 1)² + 8. Is it a maximum or a minimum?
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(1, 8), a maximum (a = −2 is negative) - Find the vertex of y = x² + 4.
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b = 0, so x = 0 and y = 4: (0, 4) - Find the vertex of y = x² − 4x + 7.
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x = 4 ÷ 2 = 2; y = 4 − 8 + 7 = 3: (2, 3) - Find the vertex of y = x² + 10x + 21.
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x = −10 ÷ 2 = −5; y = 25 − 50 + 21 = −4: (−5, −4) - Find the vertex of y = 2x² − 12x + 13.
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x = 12 ÷ 4 = 3; y = 18 − 36 + 13 = −5: (3, −5) - Find the vertex of y = −x² + 6x − 2.
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x = −6 ÷ (−2) = 3; y = −9 + 18 − 2 = 7: (3, 7), a maximum - Find the vertex of y = 3x² + 6x + 1.
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x = −6 ÷ 6 = −1; y = 3 − 6 + 1 = −2: (−1, −2) - Find the vertex of y = x² − 5x + 4.
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x = 5 ÷ 2 = 2.5; y = 6.25 − 12.5 + 4 = −2.25: (2.5, −2.25) - Find the vertex of y = (x − 2)(x − 8).
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x = (2 + 8) ÷ 2 = 5; y = 3 × (−3) = −9: (5, −9) - Find the vertex of y = −(x + 1)(x − 5).
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x = (−1 + 5) ÷ 2 = 2; y = −(3)(−3) = 9: (2, 9), a maximum - Write y = x² + 8x + 10 in vertex form and give the vertex.
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(x + 4)² − 16 + 10 = (x + 4)² − 6, vertex (−4, −6) - A parabola has its vertex at (2, −3) and passes through (0, 1). Find its equation in vertex form.
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y = a(x − 2)² − 3; at (0, 1): 1 = 4a − 3, so a = 1: y = (x − 2)² − 3 - What is the greatest value of y = −4x² + 8x + 5?
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x = −8 ÷ (−8) = 1; y = −4 + 8 + 5 = 9: the maximum is 9, at x = 1
Word problems
The vertex in real life
Try each one, then check your answer.
- A ball's height is h = 20t − 5t² metres after t seconds. How high does it go, and when?
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t = −20 ÷ (2 × −5) = 2; h = 40 − 20 = 20: 20 m, after 2 seconds - A rectangle is made from 40 m of fencing, so its area is A = x(20 − x) m², where x is the width. What is the largest area?
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A = −x² + 20x; x = −20 ÷ (−2) = 10; A = 10 × 10: 100 m² (a 10 m by 10 m square) - Water from a fountain follows h = −5t² + 10t + 1 metres. What is its highest point?
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t = −10 ÷ (−10) = 1; h = −5 + 10 + 1: 6 m, after 1 second - A bridge arch has the shape y = −0.02x² + 2x, in metres, where x is the distance from one foot of the arch. How high is the arch?
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x = −2 ÷ (−0.04) = 50; y = −0.02 × 2500 + 100 = −50 + 100: 50 m high, 50 m from the foot - Two numbers add up to 14. What is the largest possible product?
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P = x(14 − x) = −x² + 14x; x = 7: 49 (7 × 7) - A lemonade stand's daily profit is P = −10p² + 60p − 40 dollars, where p is the price of a cup in dollars. Which price gives the most profit?
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p = −60 ÷ (−20) = 3; P = −90 + 180 − 40 = 50: $3 a cup, for a profit of $50
Questions people ask
What is the vertex formula?
For y = ax² + bx + c, the vertex is at x = −b ÷ 2a. Substitute that into the equation to get y, or use y = c − b² ÷ 4a. The vertex is the point (−b ÷ 2a, c − b² ÷ 4a).
What is vertex form?
Vertex form is y = a(x − h)² + k. The vertex is (h, k), so you can read it straight off. y = 2(x − 3)² + 1 has its vertex at (3, 1).
How do you find the vertex from two x-intercepts?
The vertex is halfway between them. Add the two x-intercepts and divide by 2 to get the x-coordinate, then substitute to find y. This works for factored (intercept) form, y = a(x − p)(x − q).
How do you find the vertex from a graph?
Look for the point where the curve turns. If it is not on a grid line, find two points on the curve at the same height: the vertex is directly halfway between them.
How do you find the vertex by completing the square?
Rewrite y = x² + bx + c as y = (x + b/2)² − (b/2)² + c. For y = x² − 6x + 5 that is (x − 3)² − 4, so the vertex is (3, −4).
What is the focus of a parabola?
The focus is a different point, inside the curve. Every point on a parabola is the same distance from the focus as from a line called the directrix, and the vertex sits exactly halfway between them. For y = ax², the focus is at (0, 1 ÷ 4a).
Can a parabola have more than one vertex?
No. A parabola has exactly one vertex and one axis of symmetry. (Ellipses and hyperbolas have two vertices on their main axis, which is where the plural “vertices” comes from.)
Quick quiz
Vertex of a parabola
Check what you know with 5 quick questions.
Question 1 of 5
What is the vertex of y = (x − 3)² + 2?
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Related topics
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Completing the square rewrites x² + bx + c as (x + b/2)² − (b/2)² + c. It solves quadratics, finds the vertex (turning point) of a parabola and proves the quadratic formula.
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