Crayonbird
Menu

Science

What is stopping distance, and how do you calculate it?

Quick answer

Stopping distance is how far a vehicle travels from the moment the driver sees a hazard until it stops. Stopping distance = thinking distance + braking distance.

Ages 13–16Secondary

In one sentence

Stopping distance is the total distance a vehicle travels from the moment the driver spots a danger until the vehicle has completely stopped.

Explained

Imagine a ball rolls into the road in front of a car. The car does not stop at the instant the driver sees it. First the driver has to notice the ball, decide to brake and move a foot to the pedal. During that time the car keeps going at full speed. Then the brakes go on, and the car still slides forward while it slows down. Physics splits the stopping distance into these two parts:

stopping distance = thinking distance + braking distance

  • car
  • rain
  • clock
Speed, the road surface and the driver's reaction time all change how far a car travels before it stops.

The thinking distance (also called reaction distance) is how far the car travels during the driver's reaction time. The car is moving at a steady speed, so you use the same idea as in speed, distance and time:

thinking distance (m) = speed (m/s) × reaction time (s)

A typical reaction time is around 0.7 seconds, but it can easily be more than a second. At 20 m/s (about 45 mph or 72 km/h) a reaction time of 0.7 s gives a thinking distance of 20 × 0.7 = 14 m, before the car has even started to slow down.

The braking distance is how far the car travels once the brakes are on. The brakes use friction to do work against the car's motion until all its kinetic energy is gone. Work done = force × distance, and kinetic energy = ½mv², so:

braking force × braking distance = ½ × mass × speed²

Rearranged with deceleration a (in m/s²), this gives braking distance = v² ÷ (2a). The key thing to notice is the square. If the speed doubles, the thinking distance doubles, but the braking distance becomes four times as long. At high speed the braking distance is by far the bigger part.

What changes each part?

  • Thinking distance gets longer with higher speed, and with anything that slows reactions: tiredness, distractions such as a phone, and alcohol or drugs.
  • Braking distance gets longer with higher speed, a heavier vehicle (more mass to stop), worn brakes or tyres, and a slippery road: wet, icy, oily or covered in leaves or gravel. The UK Highway Code says stopping distances are at least double on wet roads and can be ten times longer on ice.

This is also why speed matters so much in a crash. The momentum and the kinetic energy that must be removed both grow with speed, and kinetic energy grows with speed squared, so a car at twice the speed carries four times the energy into a collision.

Examples

Typical stopping distances for a car on a dry road, as printed in the UK Highway Code:

Speed Thinking distance Braking distance Stopping distance
20 mph 6 m 6 m 12 m
30 mph 9 m 14 m 23 m
40 mph 12 m 24 m 36 m
50 mph 15 m 38 m 53 m
60 mph 18 m 55 m 73 m
70 mph 21 m 75 m 96 m

Look at the pattern: the thinking distance goes up by the same 3 m for every extra 10 mph, but the braking distance grows faster and faster. At 70 mph the braking distance is more than three times the thinking distance.

Worked example: a car travels at 25 m/s. The driver's reaction time is 0.8 s and the brakes slow the car at 6.25 m/s². Thinking distance = 25 × 0.8 = 20 m. Braking distance = 25² ÷ (2 × 6.25) = 625 ÷ 12.5 = 50 m. Stopping distance = 20 + 50 = 70 m.

Common mistakes

  • Forgetting the thinking distance. The car keeps moving at full speed while the driver reacts. Always add both parts.
  • Thinking braking distance doubles when speed doubles. It is four times as long, because it depends on speed squared. Only the thinking distance doubles.
  • Mixing units. Convert km/h to m/s first (divide by 3.6) and keep reaction time in seconds: 0.7 s, not 700.
  • Mixing up the factors. Tiredness, alcohol and distractions affect the thinking distance; road surface, tyres, brakes and load affect the braking distance. Speed affects both.

Step by step

Step by step

  1. Get the speed in m/sIf it is in km/h, divide by 3.6 (72 km/h = 20 m/s).
  2. Find the thinking distanceMultiply the speed by the reaction time in seconds.
  3. Find the braking distanceUse v² ÷ (2a) with the deceleration, or ½mv² ÷ braking force if you are given a force.
  4. Add themStopping distance = thinking distance + braking distance.
  5. Sense-checkAt higher speed, the braking part should grow much faster than the thinking part.

Practice questions

Stopping distance calculations

Try each one, then check your answer.

  1. A car travels at 20 m/s and the driver's reaction time is 0.7 s. Find the thinking distance.
    Show answer
    20 × 0.7 = 14 m
  2. The thinking distance is 12 m and the braking distance is 28 m. Find the stopping distance.
    Show answer
    12 + 28 = 40 m
  3. A car travels at 15 m/s and the reaction time is 0.6 s. Find the thinking distance.
    Show answer
    15 × 0.6 = 9 m
  4. A distracted driver at 20 m/s has a reaction time of 1.5 s. Find the thinking distance.
    Show answer
    20 × 1.5 = 30 m
  5. At 30 m/s the thinking distance is 18 m. What is the reaction time?
    Show answer
    18 ÷ 30 = 0.6 s
  6. Convert 72 km/h into m/s.
    Show answer
    72 ÷ 3.6 = 20 m/s
  7. A car at 20 m/s brakes with a deceleration of 5 m/s². Find the braking distance.
    Show answer
    20² ÷ (2 × 5) = 400 ÷ 10 = 40 m
  8. The same car travels at 10 m/s and brakes the same way. Find the braking distance.
    Show answer
    10² ÷ (2 × 5) = 100 ÷ 10 = 10 m
  9. A car's speed doubles. By what factor does the braking distance change?
    Show answer
    2² = 4, so it is 4 times as long.
  10. A car's speed is tripled. By what factor does the braking distance change?
    Show answer
    3² = 9, so it is 9 times as long.
  11. A car travels at 25 m/s, the reaction time is 0.8 s and the deceleration is 6.25 m/s². Find the stopping distance.
    Show answer
    Thinking 25 × 0.8 = 20 m; braking 625 ÷ 12.5 = 50 m; total 70 m
  12. A 1,000 kg car moves at 20 m/s. The braking force is 8,000 N. Find the braking distance.
    Show answer
    Kinetic energy = ½ × 1,000 × 20² = 200,000 J; distance = 200,000 ÷ 8,000 = 25 m
  13. A braking force of 5,000 N stops a car in 40 m. How much work do the brakes do?
    Show answer
    5,000 × 40 = 200,000 J (200 kJ)
  14. A car at 15 m/s stops in a braking distance of 20 m. Find its deceleration.
    Show answer
    a = v² ÷ (2d) = 225 ÷ 40 = 5.625 m/s²
  15. A car at 20 m/s decelerates at 5 m/s². How long does the braking take?
    Show answer
    t = 20 ÷ 5 = 4 s

Word problems

Stopping distance in real life

Try each one, then check your answer.

  1. A cyclist rides at 6 m/s. Her reaction time is 0.8 s and her braking distance is 4 m. Find her stopping distance.
    Show answer
    6 × 0.8 = 4.8 m; 4.8 + 4 = 8.8 m
  2. A driver at 20 m/s sees a fallen tree 50 m ahead. The reaction time is 0.7 s and the deceleration is 5 m/s². Does the car stop in time?
    Show answer
    Thinking 14 m + braking 40 m = 54 m. No: it needs 54 m but has only 50 m.
  3. On a dry road a car decelerates at 8 m/s²; on ice (in this example) only at 2 m/s². Find both braking distances at 16 m/s.
    Show answer
    Dry: 256 ÷ 16 = 16 m. Ice: 256 ÷ 4 = 64 m, four times as far.
  4. Using a phone raises a driver's reaction time from 0.7 s to 1.2 s at 25 m/s. How much further does the car travel before braking?
    Show answer
    Extra time 0.5 s × 25 m/s = 12.5 m
  5. The same braking force of 9,000 N acts on an empty van (1,500 kg) and a loaded van (2,000 kg), both at 15 m/s. Find both braking distances.
    Show answer
    Empty: ½ × 1,500 × 225 = 168,750 J, ÷ 9,000 = 18.75 m. Loaded: 225,000 J ÷ 9,000 = 25 m

Questions people ask

What is the formula for stopping distance?

Stopping distance = thinking distance + braking distance. Thinking distance = speed × reaction time, and braking distance = v² ÷ (2a), where a is the deceleration. In kinematics you get the same result from v² = u² + 2as (on the GCSE equation sheet as v² − u² = 2as): with final speed v = 0 and a the size of the deceleration, s = u² ÷ (2a).

What does stopping distance depend on?

On speed (the biggest factor), on the driver (reaction time: tiredness, distractions, alcohol and drugs) and on the vehicle and road (brakes, tyres, mass, and whether the road is dry, wet or icy).

What is the stopping distance at 30 mph and at 70 mph?

The UK Highway Code gives typical values for a car on a dry road of 23 m at 30 mph (9 m thinking + 14 m braking) and 96 m at 70 mph (21 m thinking + 75 m braking). These are averages; real distances can be longer.

How do you remember stopping distances?

One popular trick works in feet: multiply the speed in mph by 2 at 20 mph, 2.5 at 30 mph, 3 at 40 mph, and so on up by 0.5 each time. That gives 40 ft, 75 ft, 120 ft, 175 ft, 240 ft and 315 ft, which match the Highway Code distances in metres (12 m to 96 m). For thinking distance alone, it is 3 m for every 10 mph.

What is the stopping distance in rain or ice?

On a wet road the Highway Code says stopping distances are at least double, and on ice they can be ten times longer, because the tyres have much less grip. The thinking distance does not change; the braking distance does.

Why does a train or a ship need so far to stop?

A train has a huge mass and steel wheels on steel rails give little friction, so it can need hundreds of metres or more. A large ship has an enormous mass and only the water to slow it, so it can take several kilometres.

What is a safe following distance?

The Highway Code advises leaving at least a two-second gap behind the vehicle in front on fast roads, and at least double that in the wet. At 20 m/s, two seconds is 40 m.

Quick quiz

Stopping distance

Check what you know with 5 quick questions.

Question 1 of 5

Stopping distance is the sum of which two distances?

Practise it

Try it

Practise forces and stopping distances with unlimited questions

Physics worksheets

Ages 12–14

Physics calculations · Basics

Ages 14–16

Physics calculations · Intermediate

Ages 16–18

Physics calculations · Advanced

See more in the library

All Physics sheets

Practise it step by step in a full course: Grade 10 Science

For grown-ups

Speed, distance and time

Speed is distance divided by time. So speed = distance ÷ time, distance = speed × time, and time = distance ÷ speed. A car that goes 150 km in 2 hours travels at 75 km/h.

Maths · Ages 10–15

Forces

A force is a push or a pull. Forces can make things start moving, speed up, slow down, change direction or change shape. They are measured in newtons.

Science · Ages 5–12

Friction

Friction is a force that acts when two surfaces rub or slide against each other. It slows things down and turns movement into heat, and it also stops us slipping.

Science · Ages 6–12

Momentum

Momentum is mass in motion: momentum = mass × velocity, p = mv, measured in kg m/s. It has a direction, and in a collision the total momentum stays the same.

Science · Ages 14–17

Acceleration

Acceleration is how quickly velocity changes. a = (v − u) ÷ t, the change in velocity divided by the time taken, measured in metres per second squared (m/s²).

Science · Ages 13–16

Density

Density is how much mass is packed into a volume. The formula is density = mass ÷ volume (ρ = m/V), measured in g/cm³ or kg/m³. Water's density is about 1 g/cm³.

Science · Ages 11–16

Back to the Learning Wiki