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Grade 9 Maths · Unit 4: Straight-line graphs

Lines through two points

Find y = mx + c for the line through two given points.

First find the gradient: m = (y₂ − y₁)/(x₂ − x₁). Then substitute one point into y = mx + c to find c.

For (3, −18) and (5, −26): m = (−26 − (−18))/(5 − 3) = −8/2 = −4. Then −18 = −4 × 3 + c, so −18 = −12 + c and c = −6. The line is y = −4x − 6. Check with the second point: −4 × 5 − 6 = −26.

Worked example

Find the equation of the line through (2, −10) and (−1, 2).

  1. m = (2 − (−10))/(−1 − 2) = 12/−3 = −4.
  2. −10 = −4 × 2 + c, so c = −2.

Answer:y = −4x − 2

Key words

gradient
change in y ÷ change in x
intercept
where the line crosses the y-axis
substitute
put a point's values into the equation
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Common Core-referenced: HSF-LE.A.2