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Grade 12 Maths · Unit 4: Further algebra and trigonometry

Exponential models

Use models like P = Aeᵏᵗ for growth and decay.

Exponential growth and decay are modelled by P = Aeᵏᵗ. A is the starting value, when t = 0. If k > 0 the quantity grows; if k < 0 it decays.

To find k from data, substitute a known value and use ln. If P = 850eᵏᵗ and P = 1200 when t = 3, then 1200/850 = e³ᵏ, so k = ln(1200/850) ÷ 3 = 0.115. Equations like 3²ˣ + 5 × 3ˣ − 6 = 0 are quadratics in 3ˣ: (3ˣ + 6)(3ˣ − 1) = 0 gives 3ˣ = 1, so x = 0.

Worked example

Solve 5ˣ⁺² = 7ˣ to 3 s.f.

  1. Take logs: (x + 2) ln 5 = x ln 7.
  2. x(ln 7 − ln 5) = 2 ln 5, so x = 2 ln 5 ÷ ln 1.4 = 9.565…

Answer:x = 9.57

Key words

exponential model
an equation like P = Aeᵏᵗ
growth constant (k)
the rate in the exponent
e
about 2.718, the natural base
Practise this

New questions every time.

Common Core-referenced: HSF-LE.A.4