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Grade 11 Science · Unit 3: Structure, moles and rates

Moles, reacting masses and concentration

Use moles to calculate reacting masses, concentrations and limiting reactants.

A mole is an amount of substance: 6.02 × 10²³ particles (the Avogadro constant). The mass of one mole of a substance in grams equals its Mr: one mole of water has a mass of 18 g. Number of moles = mass ÷ Mr. In a balanced equation, the big numbers give the ratio of moles that react.

To find a reacting mass: convert the known mass to moles, use the equation's ratio, then convert back to mass. The limiting reactant is the one that is used up first; it decides how much product forms, and the other reactant is in excess. Concentration tells you how much solute is in a volume of solution: concentration (g/dm³) = mass ÷ volume (dm³), and 1 dm³ = 1000 cm³.

Worked example

How many moles are in 88 g of carbon dioxide (Mr 44)?

  1. moles = mass ÷ Mr.
  2. 88 ÷ 44 = 2.

Answer:There are 2 moles.

Key words

mole
6.02 × 10²³ particles of a substance
Avogadro constant
6.02 × 10²³ per mole
limiting reactant
the reactant that is used up first
concentration
amount of solute per volume of solution
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NGSS-referenced: HS-PS1-7