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Grade 10 Maths · Unit 2: Trigonometry in any triangle

The sine rule

Use a/sin A = b/sin B when you know an angle and its opposite side.

In any triangle, each side divided by the sine of its opposite angle gives the same value: a/sin A = b/sin B = c/sin C. Side a is opposite angle A, and so on.

Use the sine rule when you know a side and its opposite angle, plus one more side or angle. To find a side, put the unknown on top: b = a × sin B / sin A. To find an angle, flip it: sin B = b × sin A / a. If you only know two angles, find the third first, since they add to 180°.

Worked example

∠BAC = 26°, ∠ABC = 65° and BC = 11 cm. Find AC to 1 d.p.

  1. BC is opposite A and AC is opposite B.
  2. AC = 11 × sin 65° / sin 26° = 22.74…

Answer:22.7 cm

Key words

sine rule
a/sin A = b/sin B = c/sin C
opposite pair
a side and the angle facing it
ambiguous case
when two different triangles fit the facts
Practise this

New questions every time.

Common Core-referenced: HSG-SRT.D.10, HSG-SRT.D.11